[F:1][C:2]1[CH:10]=[CH:9][C:5]([C:6]([OH:8])=O)=[CH:4][C:3]=1[CH3:11].[CH3:12][O:13][C:14](=[O:21])[C@@H:15]([CH2:17][CH:18]([CH3:20])[CH3:19])[NH2:16]>>[F:1][C:2]1[CH:10]=[CH:9][C:5]([C:6]([NH:16][C@H:15]([CH2:17][CH:18]([CH3:20])[CH3:19])[C:14]([O:13][CH3:12])=[O:21])=[O:8])=[CH:4][C:3]=1[CH3:11]Prepared in a similar manner to example 4 using 4-fluoro-3-methylbenzoic acid and D-leucine methyl ester. MS (M+H, 282).
Wird geladen…