Lithium hydride → 2-[N-(4-chlorophenyl)-N-(5-chloro-2-thenyl)amino]-4H-pyrido[3,2-e]-1,3-thiazin-4-one

Beteiligte Stoffe

Reaktionsschritte

The reaction procedure of Example 11 was followed except that 2.536 g (8.75 mmol) of 2-(4-chloroanilino)-4H-pyrido[3,2-e]-1,3-thiazin-4-one, 154 mg of lithium hydride, 1.462 g of 5-chloro-2-thenyl chloride and 40 ml of DMF were used. The resulting residue was then purified through silica gel column chromatography (eluant: chloroform). As a result, 2.643 of 2-(4-chlorophenylimino)-3-(5-chloro-2-thenyl)-2,3-dihydro-4H-pyrido[3,2-e]-1,3-thiazin-4-one (recrystallized from ethanol) was obtained as a low polarity substance, and 263 mg of 2-[N-(4-chlorophenyl)-N-(5-chloro-2-thenyl)amino]-4H-pyrido[3,2-e]-1,3-thiazin-4-one (recrystallized from a mixture of ethyl acetate and diisopropyl ether) was obtained as a high polarity substance.

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