[NH2:1][C:2]1[C:7]([C:8]#[N:9])=[C:6]([C:10]2[CH:15]=[CH:14][C:13]([O:16][CH2:17][C@H:18]3[CH2:22][O:21]C(C)(C)[O:19]3)=[CH:12][CH:11]=2)[C:5]([C:25]#[N:26])=[C:4]([S:27][CH2:28][C:29]2[N:30]=[C:31]([C:34]3[CH:39]=[CH:38][C:37]([Cl:40])=[CH:36][CH:35]=3)[O:32][CH:33]=2)[N:3]=1.Cl>C(O)C>[NH2:1][C:2]1[C:7]([C:8]#[N:9])=[C:6]([C:10]2[CH:11]=[CH:12][C:13]([O:16][CH2:17][C@H:18]([OH:19])[CH2:22][OH:21])=[CH:14][CH:15]=2)[C:5]([C:25]#[N:26])=[C:4]([S:27][CH2:28][C:29]2[N:30]=[C:31]([C:34]3[CH:35]=[CH:36][C:37]([Cl:40])=[CH:38][CH:39]=3)[O:32][CH:33]=2)[N:3]=1An amount of 127.1 g (221.4 mmol) of the compound from example 6A were suspended in 800 ml of ethanol and admixed with 800 ml of 37% strength hydrochloric acid. The mixture was stirred under reflux overnight. After cooling to room temperature, the precipitate formed was isolated by suction filtration, washed with ethanol and dried under reduced pressure at 50° C. overnight. This gave 108.3 g (92% of theory) of the target compound.
Wird geladen…