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HRID 418957Erstellt: 25. Oktober 2026

4-Bromoanisole → 6-Methoxy-10-(4-methoxy-phenyl)-5-nitro-2,3,4,4a,10,10a-hexahydro-1H-phenanthren-9-one

https://huagongshe.com/reaction/418957

Reaktionsgleichung

Beteiligte Stoffe

RolleNameHCIDEinwaage
Edukt4-BromoanisoleHCID 7730—
Edukttert-ButylphosphineHCID 123165—
EduktSodium t-butoxideHCID 23676156—
Edukt6-Methoxy-5-nitro-2,3,4,4a,10,10a-hexahydro-1H-phenanthren-9-oneHCID 66652276—
Katalysatorpalladium(II) acetateHCID 167845—
LösungsmittelTetrahydrofuranHCID 8028—
Produkt6-Methoxy-10-(4-methoxy-phenyl)-5-nitro-2,3,4,4a,10,10a-hexahydro-1H-phenanthren-9-oneHCID 6665206687,1%

Reaktionsschritte

Combine 6-Methoxy-5-nitro-2,3,4,4a,10,10a-hexahydro-1H-phenanthren-9-one (0.377 g, 1.37 mmol), 4-bromoanisole (0.258 g, 1.37 mmol), palladium acetate (15.5 mg, 0.07 mmol), t-butyl phosphine (0.042 g, 0.208 mmol), sodium t-butoxide (0.145 g, 1.51 mmol), tetrahydrofuran (12.0 mL), and stir under nitrogen atmosphere at 80° C. in a glass bomb. After 18 hours, quench reaction with acetic acid (5 mL) in a glove box and extract with ethyl acetate. Wash the ethyl acetate with sodium bicarbonate solution and then brine, dry over sodium sulfate, and concentrate in vacuum. Flash chromatograph using 0% to 20% ethyl acetate/hexanes to yield the titled compound (0.455 g, 87%) as a yellow foam. TLC Rf=0.16 in 6:1 hexanes:ethyl acetate. 1H NMR (CDCl3): 8.23 (d, 1H, J=8.8 Hz), 7.06 (m, 3H), 6.92 (m, 2H), 4.01 (m, 4H), 3.83 (s, 3H), 3.10 (dt, 1H, J=8.4, 4.3 Hz), 2.76 (m, 1H), 1.82 (m, 4H), 1.47 (m, 4H).

Herkunft & Nachweise

DOI10.6084/m9.figshare.5104873.v1
PatentnummerUS08093302B2
Quelldatensatzuspto-grants-2012_01
ORD IDord-6cc9a4fbac8d4d9a9d2f9e2edbfb79ed
Quellennotizuspto-grants-2012_01