Boron tribromide → 4-Bromocatechol

Beteiligte Stoffe

Reaktionsschritte

6.51 g (0.0300 mol) of 4-bromoveratrole is dissolved in 50 ml of dichloromethane. To this suspension is added 37.6 g (0.150 mol) of boron tribromide at 0° C. The mixture was stirred for 3 hours at room temperature. Solvents were removed under reduced pressure. The resulting brown oil was dissolved in ethyl acetate and filtered through a pad of silica gel. The filtrate was concentrated to afford 5.45 g of 4-bromo catechol as a fight, brown oil.

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