Iodine → 2-Amino-4-(4-methoxyphenyl)thiazole

Reaktionsgleichung

[NH2:1][C:2]([NH2:4])=[S:3].[CH3:5][C:6]([C:8]1[CH:13]=[CH:12][C:11]([O:14][CH3:15])=[CH:10][CH:9]=1)=O.II>>[CH3:15][O:14][C:11]1[CH:12]=[CH:13][C:8]([C:6]2[N:1]=[C:2]([NH2:4])[S:3][CH:5]=2)=[CH:9][CH:10]=1

Komponenten

Edukt 3

HCID 807Iodine

HCID 74764'-Methoxyacetophenone

HCID 2723790Thiourea

Produkt 1

HCID 1596442-Amino-4-(4-methoxyphenyl)thiazoleAusbeute 91,7 %

Versuchsvorschrift

33.5 g of thiourea are added to 30 g of 4-methoxyacetophenone, 56 g of iodine are added and the mixture is kept at 100° C. for 5 hours. The reaction mixture is discharged onto water, powdered, washed several times with ether then with ammonia solution and finally with water, and dried. 37.8 g of 4-(4-methoxyphenyl)-thiazol-2-yl-amine of melting point 194°-205° C. are obtained.