Dichloromethane → Dimethyl terephthalate

Reaktionsgleichung

[C:1]([OH:12])(=[O:11])[C:2]1[CH:10]=[CH:9][C:5]([C:6]([OH:8])=O)=[CH:4][CH:3]=1.Cl[CH2:14]Cl.[C:16](Cl)(Cl)=[O:17]>N1C=CC=CC=1>[C:6]([O:17][CH3:16])(=[O:8])[C:5]1[CH:4]=[CH:3][C:2]([C:1]([O:12][CH3:14])=[O:11])=[CH:10][CH:9]=1

Komponenten

Versuchsvorschrift

Following the general procedure of Example 9, a slurry of 8.28 parts terephthalic acid in 80 parts dry dichloromethane was added to a stirred mixture of 8.72 parts pyridine and 10.84 parts phosgene in 210 parts dry dichloromethane at 24° to 30° C. The ratio of equivalents of pyridine base/COOH acid groups was 1.10. After carrying out the reaction and esterifying the resulting diacid chloride by the procedure described in Example 1, there was obtained a 100% yield of dimethyl terephthalate, corresponding to a 100% yield of terephthaloyl chloride, formed initially in the reaction.