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HuagongsheHuagongshe Chemie-Druckbericht · Nur für Forschungszwecke
HRID 8284Erstellt: 23. Oktober 2026

Lithium Hydroxide → 3-{4-[2-(6-Methyl-pyridin-2-yl)-5,6-dihydro-4H-pyrrolo[1,2-b]pyrazol-3-yl]-quinolin-6-yl}-acrylic Acid

https://huagongshe.com/de/reaction/8284

Reaktionsgleichung

Beteiligte Stoffe

RolleNameHCIDEinwaage
EduktLithium HydroxideHCID 3939—
Edukt3-{4-[2-(6-methyl-pyridin-2-yl)-5,6-dihydro-4H-pyrrolo[1,2-b]pyrazol-3-yl]-quinolin-6-yl}-acrylic acid methyl esterHCID 66679269—
LösungsmittelMethanol--water (1/1)HCID 22242641—
ProduktAmmonia methanolHCID 21705897—
Produkt3-{4-[2-(6-Methyl-pyridin-2-yl)-5,6-dihydro-4H-pyrrolo[1,2-b]pyrazol-3-yl]-quinolin-6-yl}-acrylic AcidHCID 66678074181,6%

Reaktionsschritte

Dissolve 3-{4-[2-(6-methyl-pyridin-2-yl)-5,6-dihydro-4H-pyrrolo[1,2-b]pyrazol-3-yl]-quinolin-6-yl}-acrylic acid methyl ester (0.040 g, 0.1 mmol) in methanol/water (3:1, 2 mL). Add lithium hydroxide (0.010 g, 0.25 mmol) and stir the mixture 18 h. Remove the solvent then load the residue on a SCX resin column with methanol. Elute the column with methanol (50 mL) then with 2 N ammonia/methanol to give the desired product as a pale yellow solid 0.036 g (92%)

Herkunft & Nachweise

DOI10.6084/m9.figshare.5104873.v1
PatentnummerUS07087626B2
Quelldatensatzuspto-grants-2006_08
ORD IDord-ea1e8d4f720a4896a3c22d426cba3c83
Quellennotizuspto-grants-2006_08