[C:1]1([OH:7])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.[C:8]([O-])([O-:13])([O:10]CC)C>>[OH:7][C@H:1]1[CH2:6][CH:5]=[CH:4][C@H:3]1[CH2:2][C:8]([OH:13])=[O:10]In the same manner as described in Example 1 but using 0.5 part of phenol in place of the hydroquinone, 7 parts of unreacted ethyl orthoacetate was recovered and then 4.2 parts of the desired product, a lactone of cis-2-hydroxy-cyclopent-4-ene-1-acetic acid was obtained.
Wird geladen…