4-Hydroxybenzoic Acid → 4-(6-Hydroxyhexyloxy)benzoic acid
Reaction equation
[OH:1][C:2]1[CH:10]=[CH:9][C:5]([C:6]([OH:8])=[O:7])=[CH:4][CH:3]=1.Cl[CH2:12][CH2:13][CH2:14][CH2:15][CH2:16][CH2:17][OH:18]>[OH-].[K+]>[OH:18][CH2:17][CH2:16][CH2:15][CH2:14][CH2:13][CH2:12][O:1][C:2]1[CH:10]=[CH:9][C:5]([C:6]([OH:8])=[O:7])=[CH:4][CH:3]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 60 °C
Procedure
Monomers in which the bulky organic group was a t-butyl group and the alkyl groups were hexyl groups were made as follows. 4-hydroxybenzoic acid was dissolved in 30% ethanolic KOH. About 1% of KI was added as a catalyst. The mixture was heated to about 60° C. and a stoichiometric amount of 6-chloro-1-hexanol was slowly added over about ½ hour. After refluxing the reaction mixture for extended period of time (2-15 hrs) the contents was cooled, the reaction mixture was filtered off, and the filtrate solvent was evaporated under vacuum. Water was added into the residue and acidified with HCl and the precipitate was filtered and crystallized with ethanol, yielding approximately an 80% 4-(6-hydroxyhexyloxy)-benzoic acid.