[CH3:1][C:2]1[CH:8]=[CH:7][C:5]([NH2:6])=[CH:4][C:3]=1[N:9]1[C:16]2[N:12]([N:13]=[C:14]([C:17]3[CH:18]=[N:19][CH:20]=[CH:21][CH:22]=3)[CH:15]=2)[CH:11]=[CH:10]1.[CH3:23][C:24]1[CH:25]=[C:26]([CH:30]=[C:31]([S:33]([F:38])([F:37])([F:36])([F:35])[F:34])[CH:32]=1)[C:27](O)=[O:28]>>[CH3:23][C:24]1[CH:25]=[C:26]([CH:30]=[C:31]([S:33]([F:36])([F:34])([F:35])([F:37])[F:38])[CH:32]=1)[C:27]([NH:6][C:5]1[CH:7]=[CH:8][C:2]([CH3:1])=[C:3]([N:9]2[C:16]3[N:12]([N:13]=[C:14]([C:17]4[CH:18]=[N:19][CH:20]=[CH:21][CH:22]=4)[CH:15]=3)[CH:11]=[CH:10]2)[CH:4]=1)=[O:28]Analogously to the process described in Example 26, 80 mg (0.276 mmol) of the compound of Example 6A and 73 mg (0.276 mmol) of the compound of Example 34A gave 101 mg (61% of theory, 90% pure) of the title compound.
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