FC1C=CC(C)=CC=1CO.[F:11][C:12]1[CH:19]=[CH:18][C:17]([Cl:20])=[CH:16][C:13]=1[CH:14]=[O:15]>>[F:11][C:12]1[CH:19]=[CH:18][C:17]([Cl:20])=[CH:16][C:13]=1[CH2:14][OH:15]The title intermediate was prepared essentially as was 2-fluoro-5-methylbenzyl alcohol, supra, except that an equimolar amount of 2-fluoro-5-chlorobenzaldehyde was employed instead of the 2-fluoro-5-methylbenzaldehyde employed therein.
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