Water → 1,2-Propanediamine, N-(4-nitrophenyl)-

Reaction equation

[N+:1]([C:4]1[CH:9]=[CH:8][C:7](F)=[CH:6][CH:5]=1)([O-:3])=[O:2].O.[CH2:12]([NH2:16])[CH:13]([NH2:15])[CH3:14]>>[N+:1]([C:4]1[CH:9]=[CH:8][C:7]([NH:16][CH2:12][CH:13]([NH2:15])[CH3:14])=[CH:6][CH:5]=1)([O-:3])=[O:2]

Participants

Reactant 3

HCID 962Water

HCID 6567Propylenediamine

HCID 9590p-Fluoronitrobenzene

Product 1

HCID 41444141,2-Propanediamine, N-(4-nitrophenyl)-Yield 92.9%

Procedure

2.8 g of 4-nitrofluorobenzene were heated to 80° C. in 29.6 g of propylenediamine and then stirred for 1 hour at the same temperature. The reaction mixture was poured into water and precipitated crystals were collected by filtration, thereby obtaining 3.6 g of N-(4-nitrophenyl)propylenediamine as crystals.