F[C:2]1[CH:7]=[CH:6][C:5]([S:8]([Cl:11])(=[O:10])=[O:9])=[CH:4][C:3]=1[O:12][CH3:13].[Cl:14]C1C=CC(OC)=CC=1N>>[Cl:14][C:6]1[CH:7]=[CH:2][C:3]([O:12][CH3:13])=[CH:4][C:5]=1[S:8]([Cl:11])(=[O:10])=[O:9]The titled compound is prepared analogously to 4-fluoro-3-methoxy-benzenesulfonyl chloride (Intermediate 102a) by replacing 4-fluoro-3-methoxyaniline with 2-chloro-5-methoxy-phenylamine.
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