(1-Fluorocyclohexyl)methanol → HCID 66575808, compound
Reaction equation
F[C:2]1[CH:7]=[C:6]([F:8])[CH:5]=[CH:4][C:3]=1[C:9]1[N:14]=[CH:13][N:12]=[C:11]([NH:15][C:16]2[CH:21]=[CH:20][CH:19]=[C:18]([CH2:22][S:23]([CH3:26])(=[O:25])=[O:24])[CH:17]=2)[N:10]=1.[F:27][C:28]1([CH2:34][OH:35])[CH2:33][CH2:32][CH2:31][CH2:30][CH2:29]1>>[F:8][C:6]1[CH:5]=[CH:4][C:3]([C:9]2[N:14]=[CH:13][N:12]=[C:11]([NH:15][C:16]3[CH:21]=[CH:20][CH:19]=[C:18]([CH2:22][S:23]([CH3:26])(=[O:25])=[O:24])[CH:17]=3)[N:10]=2)=[C:2]([O:35][CH2:34][C:28]2([F:27])[CH2:33][CH2:32][CH2:31][CH2:30][CH2:29]2)[CH:7]=1Participants
3
Procedure
Starting with 4-(2,4-difluorophenyl)-N-{3-[(methylsulfonyl)methyl]phenyl}-1,3,5-triazin-2-amine (80 mg; 0.21 mmol), intermediate 42.1, and (1-fluorocyclohexyl)methanol (117 mg; 0.841 mmol), example 66 was prepared analogously to the procedure for the preparation of example 42.
Workup
- customwas prepared analogously to the procedure for the preparation of example 42