Lithium hydride → 4-(4-Ethoxyphenyl)-2-fluoro-4-methylpent-2-enol
Reaction equation
[F:1][C:2](=[CH:7][C:8]([C:11]1[CH:16]=[CH:15][C:14]([O:17][CH2:18][CH3:19])=[CH:13][CH:12]=1)([CH3:10])[CH3:9])[C:3](OC)=[O:4].[H-].[Li+]>C(OCC)C>[CH2:18]([O:17][C:14]1[CH:15]=[CH:16][C:11]([C:8]([CH3:9])([CH3:10])[CH:7]=[C:2]([F:1])[CH2:3][OH:4])=[CH:12][CH:13]=1)[CH3:19]Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
The method of Example 6 was repeated using methyl 2-fluoro-4-(4-ethoxy-phenyl)-4-methylpent-2-enoate (Example 4) (0.2 g), diethyl ether (15 ml) and lithium hydride (0.1 g) to yield the title compound (0.16 g, 90%).
Sources & evidence
- ORD record
- ord-447b5bac63ac4362b88372f90bb8017a
- Source dataset
- uspto-grants-1999_03
- Patent number
- US05880162
Reaction notes
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