Succinic Acid → Nilotinib succinate
Reaction equation
[CH3:1][C:2]1[CH:3]=[CH:4][C:5]([C:21]([NH:23][C:24]2[CH:25]=[C:26]([C:36]([F:39])([F:38])[F:37])[CH:27]=[C:28]([N:30]3[CH:34]=[N:33][C:32]([CH3:35])=[CH:31]3)[CH:29]=2)=[O:22])=[CH:6][C:7]=1[NH:8][C:9]1[N:10]=[CH:11][CH:12]=[C:13]([C:15]2[CH:16]=[CH:17][CH:18]=[N:19][CH:20]=2)[N:14]=1.[C:40]([OH:47])(=[O:46])[CH2:41][CH2:42][C:43]([OH:45])=[O:44]>>[CH3:1][C:2]1[CH:3]=[CH:4][C:5]([C:21]([NH:23][C:24]2[CH:25]=[C:26]([C:36]([F:38])([F:39])[F:37])[CH:27]=[C:28]([N:30]3[CH:34]=[N:33][C:32]([CH3:35])=[CH:31]3)[CH:29]=2)=[O:22])=[CH:6][C:7]=1[NH:8][C:9]1[N:10]=[CH:11][CH:12]=[C:13]([C:15]2[CH:16]=[CH:17][CH:18]=[N:19][CH:20]=2)[N:14]=1.[C:40]([O-:47])(=[O:46])[CH2:41][CH2:42][C:43]([O-:45])=[O:44]Participants
3
Reactant 2
Product 1
Conditions
- Temperature
- 5 °C
Procedure
Nilotinib base (0.300 g, 0.57 mmol) was dissolved in TFE (2 mL) at 40° C. to obtain a mixture. The mixture was stirred and added to a solution of succinic acid (0.066 g, 0.57 mmol) in TFE (1 mL) at 40° C. The resulting solution was stirred for about 4 h and subsequently cooled to 5° C. The mixture was kept at 5° C. overnight and then a sample (1 mL) was taken from the mixture and evaporated to dryness under reduced pressure at 40° C. to give Nilotinib succinate form II.
Workup
- customto obtain a mixture