Sodium Hydroxide → HCID 178488543, compound
Reaction equation
I.[CH3:2][O:3][C:4]1[CH:9]=[CH:8][C:7]([C:10]2[CH:15]=[CH:14][CH:13]=[CH:12][C:11]=2[NH:16][C:17](=[NH:20])[S:18][CH3:19])=[CH:6][CH:5]=1.[OH-].[Na+]>ClCCl>[CH3:2][O:3][C:4]1[CH:5]=[CH:6][C:7]([C:10]2[CH:15]=[CH:14][CH:13]=[CH:12][C:11]=2[NH:16][C:17](=[NH:20])[S:18][CH3:19])=[CH:8][CH:9]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
Reaction of N-(4'-methoxy-2-biphenylyl)thiourea (14.7 g) with methyliodide (9.3 g) in methanol (60 ml) at gentle reflux on a hot water bath for 3 hours gave 1-(4'-methoxy-2-biphenylyl)-2-methyl-2-thiopseudourea hydroiodide as a semisolid. Reaction of the above hydroiodide (8 g) in dichloromethane (100 ml) with 10% aqueous sodium hydroxide solution (25 ml) at 0° C. gave 1-(4'-methoxy-2-biphenylyl)-2-methyl-2-thiopseudourea as a pale yellow solid (m.p. 94°-96° C.).