1H-Indene, 2-(1-methylethyl)-4-phenyl- → Lithium 2-isopropyl-4-phenylindenide
Reaction equation
[CH:1]([C:4]1[CH2:5][C:6]2[C:11]([CH:12]=1)=[C:10]([C:13]1[CH:18]=[CH:17][CH:16]=[CH:15][CH:14]=1)[CH:9]=[CH:8][CH:7]=2)([CH3:3])[CH3:2].C([Li:23])CCC>C1(C)C=CC=CC=1>[CH:1]([C:4]1[CH-:5][C:6]2[C:11]([CH:12]=1)=[C:10]([C:13]1[CH:18]=[CH:17][CH:16]=[CH:15][CH:14]=1)[CH:9]=[CH:8][CH:7]=2)([CH3:3])[CH3:2].[Li+:23]Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
To a toluene solution (25 ml) of 2-isopropyl-4-phenylindene (3.34 g, 14.25 mmol), in a glovebox filled with argon, was added n-butyl lithium (5.500 ml, 13.75 mmol). The mixture was stirred at room temperature overnight. The toluene was removed under reduced pressure. Hexane (20 ml) was added and removed under reduced pressure then added again (50 ml). The mixture was stirred for 1 h then filtered, washed with about 15 ml hexane and the filtrate dried under vacuum. The lithium indenide product (3.09 g) was obtained as an orange-brown powder. This material was stored in the glovebox until needed.