[CH:1]1[C:11]2[CH:10]=[CH:9][C:8]3[CH:12]=[CH:13][CH:14]=[CH:15][C:7]=3[S:6][C:5]=2[CH:4]=[C:3]([C:16](O)=[O:17])[CH:2]=1.C1C2CCC3C=CC=CC=3SC=2C=C(C(O)=O)C=1>>[OH:17][CH2:16][C:3]1[CH:2]=[CH:1][C:11]2[CH:10]=[CH:9][C:8]3[CH:12]=[CH:13][CH:14]=[CH:15][C:7]=3[S:6][C:5]=2[CH:4]=1Repeat the process of Example 1, substituting an equivalent quantity of dibenzo[b,f]thiepin-3-carboxylic acid for the 10,11-dihydrodibenzo[b,f]thiepin-3-carboxylic acid, to obtain the title product (m.p., 111°-112° C.).
Loading…