[F:1][C:2]1[CH:3]=[CH:4][C:5]2[S:11][C:10]3[CH:12]=[C:13]([C:16](O)=[O:17])[CH:14]=[CH:15][C:9]=3[CH2:8][CH2:7][C:6]=2[CH:19]=1.C1C2CCC3C=CC=CC=3SC=2C=C(C(O)=O)C=1>>[F:1][C:2]1[CH:3]=[CH:4][C:5]2[S:11][C:10]3[CH:12]=[C:13]([CH2:16][OH:17])[CH:14]=[CH:15][C:9]=3[CH2:8][CH2:7][C:6]=2[CH:19]=1Repeat the process of Example 1, substituting an equivalent quantity of 8-fluoro-10,11-dihydrodibenzo[b,f]thiepin-3-carboxylic acid for the 10,11-dihydrodibenzo[b,f]thiepin-3-carboxylic acid, to obtain the title product (m.p., 80°-81° C.).
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