Isopropyl iodide → 2-Nitro-5-(2-propyloxy)benzyl alcohol
Reaction equation
[OH:1][C:2]1[CH:3]=[CH:4][C:5]([N+:10]([O-:12])=[O:11])=[C:6]([CH:9]=1)[CH2:7][OH:8].[CH:13](I)([CH3:15])[CH3:14]>>[N+:10]([C:5]1[CH:4]=[CH:3][C:2]([O:1][CH:13]([CH3:15])[CH3:14])=[CH:9][C:6]=1[CH2:7][OH:8])([O-:12])=[O:11]Participants
3
Procedure
10 g (60 mmol) of 5-hydroxy-2-nitrobenzyl alcohol were reacted with 7.0 ml (70 mmol) of isopropyl iodide analogously to Example 4a); after purification over silica gel with n-heptane/ethyl acetate (3:2), 10.3 g of oily crude product.
Workup
- customafter purification over silica gel with n-heptane/ethyl acetate (3:2), 10.3 g of oily crude product
Sources & evidence
- ORD record
- ord-61857a4aa4ad49af8aac9e9223a18f71
- Source dataset
- uspto-grants-1998_03
- Patent number
- US05726305
Reaction notes
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