Reaction equation
[CH:1]1[C:13]2[C:12](=O)[C:11]3[C:6](=[CH:7][CH:8]=[CH:9][CH:10]=3)[C:5]=2[CH:4]=[CH:3][CH:2]=1.[NH2:15][NH2:16]>>[CH:1]1[C:13]2[C:12](=[N:15][NH2:16])[C:11]3[C:6](=[CH:7][CH:8]=[CH:9][CH:10]=3)[C:5]=2[CH:4]=[CH:3][CH:2]=1Participants
3
Reactant 2
Product 1
Procedure
Symmetrical charge transport materials can be prepared by the following procedure. In the first step a 9-fluorenone or a derivative compound reacts with an excess of hydrazine at 50-70° C. for 1-6 hours to produce a 9-fluorenone hydrazone compound or derivative thereof. Then, the 9-fluorenone hydrazone compound can be isolated and purified. In the next step, the 9-fluorenone hydrazone reacts with a linking compound having 2 aldehyde groups or ketone groups, such as OCH—CHO, a quinone derivative, or a diphenoquinone derivative, in a mole ratio of 2:1 (2 mole of hydrazine derivative with 1 mole of the linking compound). The desired product can be isolated and purified by recrystalization or/and column chromatography.
Workup
- additionSymmetrical charge transport materials
- customcan be prepared by the following procedure
Sources & evidence
- ORD record
- ord-e3ae525c31934931932ff4147ee1322c
- Source dataset
- uspto-grants-2009_03
- Patent number
- US07501216B2
Linked notes
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