Water → 3-Fluoro-5-methoxy-4-nitrobenzoic acid

Reaction equation

[F:1][C:2]1[CH:3]=[C:4]([CH:7]=[C:8]([O:13][CH3:14])[C:9]=1[N+:10]([O-:12])=[O:11])[C:5]#N.[OH:15]S(O)(=O)=O.[OH2:20]>>[F:1][C:2]1[CH:3]=[C:4]([CH:7]=[C:8]([O:13][CH3:14])[C:9]=1[N+:10]([O-:12])=[O:11])[C:5]([OH:15])=[O:20]

Participants

Reactant 3

HCID 962Water

HCID 1118Sulfuric Acid

HCID 579555403-Fluoro-5-methoxy-4-nitrobenzonitrile

Product 1

HCID 579555223-Fluoro-5-methoxy-4-nitrobenzoic acidYield 75%

Conditions

Temperature: 100 °C

Procedure

A suspension of 3-fluoro-5-methoxy-4-nitrobenzonitrile (940 mg, 4.8 mmol) in a mixture of concentrated H2SO4 and water (2 mL/2 mL) was heated at 100° C. overnight. The reaction mixture was then cooled down, solid filtered and dried to give the product as brown solid (770 mg, 75%).