Bromine → HCID 15580980, compound
Reaction equation
O[CH:2]([C:14]1[CH:19]=[CH:18][CH:17]=[CH:16][CH:15]=1)[CH2:3][NH:4][C:5]([NH:7][C:8]1[CH:13]=[CH:12][CH:11]=[CH:10][CH:9]=1)=[S:6].BrBr>ClC(Cl)(Cl)Cl>[C:14]1([CH:2]2[N:7]3[C:5]([S:6][C:9]4[CH:10]=[CH:11][CH:12]=[CH:13][C:8]=43)=[N:4][CH2:3]2)[CH:19]=[CH:18][CH:17]=[CH:16][CH:15]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
A mixture of 50 parts of N-(2-hydroxy-2-phenylethyl)-N'-phenylthiourea, 30 parts of bromine and 800 parts of tetrachloromethane is stirred and refluxed for 2 hours. The reaction mixture is evaporated. From the residue, the free base is liberated in the conventional manner with ammonium hydroxide and extracted with trichloromethane. The extract is dried, filtered and evaporated. The residue is suspended in boiling 4-methyl-2-pentanone. The product is filtered off and stirred in a diluted sodium hydroxide solution. The product is extracted with 4-methyl-2-pentanone. The extract is washed with water, dried, filtered and evaporated. The residue is crystallized from acetonitrile. The product is filtered off and dried, yielding 10 parts (22%) of 2,3-dihydro-3-phenylimidazo[2,1-b]benzothiazole; mp. 131.7° C.