2-(4-Methylphenyl)ethoxyacetic acid → 2-[2-(4-Methylphenyl)ethoxy]ethanol
Reaction equation
[CH3:1][C:2]1[CH:7]=[CH:6][C:5]([CH2:8][CH2:9][O:10][CH2:11][C:12](O)=[O:13])=[CH:4][CH:3]=1.[H-].[Al+3].[Li+].[H-].[H-].[H-]>>[CH3:1][C:2]1[CH:3]=[CH:4][C:5]([CH2:8][CH2:9][O:10][CH2:11][CH2:12][OH:13])=[CH:6][CH:7]=1Participants
3
Procedure
The 2-(4-methylphenyl)ethoxyacetic acid obtained according to the preceding paragraph was reduced with lithium aluminum hydride in a manner analogous to that described in Example 1(b) to give 6.6 g (88%) of 2-[2-(4-methylphenyl)ethoxy]ethanol in the form of an oil which was homogeneous according to chromatography.
Sources & evidence
- ORD record
- ord-a92922499a7c40edb70a961b4848b83e
- Source dataset
- uspto-grants-1987_03
- Patent number
- US04649160
Reaction notes
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