Lithium hydride → 2-[2-(4-Chlorophenyl)ethoxy]ethanol

Reaction equation

[Cl:1][C:2]1[CH:7]=[CH:6][C:5]([CH2:8][CH2:9][O:10][CH2:11][C:12](O)=[O:13])=[CH:4][CH:3]=1.[H-].[Li+]>>[Cl:1][C:2]1[CH:3]=[CH:4][C:5]([CH2:8][CH2:9][O:10][CH2:11][CH2:12][OH:13])=[CH:6][CH:7]=1

Participants

Reactant 2

HCID 62714Lithium hydride

HCID 132089252-(4-Chlorophenyl)ethoxyacetic acid

Product 1

HCID 132089322-[2-(4-Chlorophenyl)ethoxy]ethanolYield 43%

Procedure

The 2-(4-chlorophenyl)ethoxyacetic acid obtained according to the preceding paragraph was reduced with lithium hydride in a manner analogous to that described in Example 1(b) to give 1.6 g (43%) of 2-[2-(4-chlorophenyl)-ethoxy]ethanol in the form of an oil which was homogeneous according to chromatography.

Sources & evidence

ORD record: ord-c3916a6542b341d580daca114280fbfe
Source dataset: uspto-grants-1987_03
DOI: 10.6084/m9.figshare.5104873.v1
Patent number: US04649160

Reaction notes

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