3,6-Dimethylpyridazine → 3,6-Di(3-chloro-4-nitrostyryl)-pyridazine
Reaction equation
[CH3:1][C:2]1[N:3]=[N:4][C:5]([CH3:8])=[CH:6][CH:7]=1.[Cl:9][C:10]1[CH:11]=[C:12]([CH:15]=[CH:16][C:17]=1[N+:18]([O-:20])=[O:19])[CH:13]=O>C(OC(=O)C)(=O)C>[Cl:9][C:10]1[CH:11]=[C:12]([CH:15]=[CH:16][C:17]=1[N+:18]([O-:20])=[O:19])[CH:13]=[CH:1][C:2]1[N:3]=[N:4][C:5]([CH:8]=[CH:13][C:12]2[CH:15]=[CH:16][C:17]([N+:18]([O-:20])=[O:19])=[C:10]([Cl:9])[CH:11]=2)=[CH:6][CH:7]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
First, 28 g of 3,6-dimethylpyridazine and 98 g of 3-chloro-4-nitrobenzaldehyde were dissolved in 1.5 liters of acetic anhydride to produce 21 g of 3,6-di(3-chloro-4-nitrostyryl)-pyridazine.