Potassium Hydroxide → HCID 25190386, compound
Reaction equation
[F:1][C:2]([F:35])([F:34])[C:3]1[CH:11]=[C:10]([C:12]#[N:13])[CH:9]=[C:8]2[C:4]=1[C:5]([NH:22][C:23](=[O:33])[CH2:24][N:25]1[CH2:30][CH2:29][N:28]([CH2:31][CH3:32])[CH2:27][CH2:26]1)([C:15]1[CH:20]=[CH:19][C:18]([Cl:21])=[CH:17][CH:16]=1)[C:6](=[O:14])[NH:7]2.[OH-:36].[K+]>CC(O)(C)C>[Cl:21][C:18]1[CH:17]=[CH:16][C:15]([C:5]2([NH:22][C:23](=[O:33])[CH2:24][N:25]3[CH2:26][CH2:27][N:28]([CH2:31][CH3:32])[CH2:29][CH2:30]3)[C:4]3[C:8](=[CH:9][C:10]([C:12]([NH2:13])=[O:36])=[CH:11][C:3]=3[C:2]([F:1])([F:34])[F:35])[NH:7][C:6]2=[O:14])=[CH:20][CH:19]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
0.16 g of the product obtained in Example 4, 0.47 g of potassium hydroxide and 7 ml of t-BuOH are placed in a round-bottomed flask equipped with a magnetic stirrer. The mixture is left to react at 50° C. for 5 hours. The resulting mixture is filtered through Celite and washed with THF. The filtrate is evaporated under vacuum and the residue is taken up in ethyl acetate and washed with water. The organic phase is dried over Na2SO4, filtered and evaporated under vacuum. 100 mg of an oil are obtained, which oil is purified by flash chromatography, eluting with 8/2 ethyl acetate/methanol. 10 mg of white solid are isolated.