4-(5-Fluoro-2-methoxy-phenyl)-2-hydroxy-4-methyl-2-(trifluoromethyl)pentanal → 4-(5-Fluoro-2-methoxyphenyl)-1-(2-quinolon-5-ylamino)-4-methyl-2-(trifluoromethyl)pentan-2-ol

HRID 2215396

Reaction equation

HRID 2215396 reaction equation
[F:1][C:2]1[CH:3]=[CH:4][C:5]([O:20][CH3:21])=[C:6]([C:8]([CH3:19])([CH3:18])[CH2:9][C:10]([OH:17])([C:13]([F:16])([F:15])[F:14])[CH:11]=O)[CH:7]=1.[NH2:22][C:23]1[CH:32]=[CH:31][CH:30]=[C:29]2[C:24]=1[CH:25]=[CH:26][C:27](=[O:33])[NH:28]2>>[F:1][C:2]1[CH:3]=[CH:4][C:5]([O:20][CH3:21])=[C:6]([C:8]([CH3:18])([CH3:19])[CH2:9][C:10]([C:13]([F:15])([F:16])[F:14])([OH:17])[CH2:11][NH:22][C:23]2[CH:32]=[CH:31][CH:30]=[C:29]3[C:24]=2[CH:25]=[CH:26][C:27](=[O:33])[NH:28]3)[CH:7]=1

Participants

3

Reactant 2

HCID 115731224-(5-Fluoro-2-methoxy-phenyl)-2-hydroxy-4-methyl-2-(trifluoromethyl)pentanalHCID 157190785-Amino-1,2-dihydroquinolin-2-one

Product 1

HCID 219488164-(5-Fluoro-2-methoxyphenyl)-1-(2-quinolon-5-ylamino)-4-methyl-2-(trifluoromethyl)pentan-2-olYield 60.6%

Procedure

Analogously to Example 20, 226 mg (0.73 mmol) of 4-(5-fluoro-2-methoxyphenyl)-2-hydroxy-4-methyl-2-(trifluoromethyl)pentanal and 140 mg (0.87 mmol) of 5-amino-2-quinolone are reacted to form 200 mg of the product.

Sources & evidence

ORD record
ord-8858bcdd6c03457dbd44b0333f26216a
Source dataset
uspto-grants-2006_09
Patent number
US07109212B2

Linked notes

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