Sodium Methoxide → 7-Fluoro-2-methoxy-8-methylquinoxaline
Reaction equation
Cl[C:2]1[CH:11]=[N:10][C:9]2[C:4](=[C:5]([CH3:13])[C:6]([F:12])=[CH:7][CH:8]=2)[N:3]=1.[CH3:14][O-:15].[Na+]>CO>[F:12][C:6]1[C:5]([CH3:13])=[C:4]2[C:9]([N:10]=[CH:11][C:2]([O:15][CH3:14])=[N:3]2)=[CH:8][CH:7]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
2-Chloro-7-fluoro-8-methylquinoxaline (4.1 g, 20.9 mmol) was suspended in dry methanol and a 25% solution of sodium methoxide in methanol (4.73 ml, 21.9 mmol) was added by syringe. The mixture was heated under reflux for 2 h, then evaporated. The residue was dissolved in dichloromethane and water and the phases were separated. The aqueous phase was extracted twice with dichloromethane, and combined organic fractions were dried and evaporated to give product (3.84 g, 96%).