3-Hydroxybenzyl alcohol → 3-(4-formylphenoxy)Benzonitrile
Reaction equation
F[C:2]1[CH:9]=[CH:8][C:5]([CH:6]=[O:7])=[CH:4][CH:3]=1.OC1C=C(C=CC=1)CO.[OH:19][C:20]1[CH:21]=[C:22]([CH:25]=[CH:26][CH:27]=1)[C:23]#[N:24].C1C(C#N)=CN=C(Cl)C=1>>[CH:6]([C:5]1[CH:8]=[CH:9][C:2]([O:19][C:20]2[CH:21]=[C:22]([CH:25]=[CH:26][CH:27]=2)[C:23]#[N:24])=[CH:3][CH:4]=1)=[O:7]Participants
5
Procedure
The title compound is prepared essentially as described in Preparation 1 substituting 4-fluorobenzaldehyde (0.85 mL, 8.06 mmol) for 3-hydroxybenzyl alcohol and 3-hydroxybenzonitrile (1.06 g, 8.86 mmol) for 6-chloronicotinitrile. Yield (0.90 g, 50%); 1H NMR (CDCl3) 10.01 (s, 1H), 7.95 (d, J=8.5 Hz, 2H), 7.58-7.52 (m, 2H), 7.39-7.34 (m, 2H), 7.14 (d, J=8.5 Hz, 2H).