Boron tribromide → HCID 18372893, compound
Reaction equation
[O:1]1[C:5]2[CH:6]=[CH:7][C:8]([C:10]3[O:11][C:12]4[C:17]([C:18](=[O:21])[C:19]=3[OH:20])=[CH:16][C:15]([O:22][CH3:23])=[CH:14][CH:13]=4)=[CH:9][C:4]=2[O:3]C1.B(Br)(Br)Br>>[OH:3][C:4]1[CH:9]=[C:8]([C:10]2[O:11][C:12]3[C:17]([C:18](=[O:21])[C:19]=2[OH:20])=[CH:16][C:15]([O:22][CH3:23])=[CH:14][CH:13]=3)[CH:7]=[CH:6][C:5]=1[OH:1]Participants
3
Procedure
The reaction was conducted according to the same procedure as Example 57 except that 50 mg (159 pmol) of the compound obtained in Example 5 instead of the compound obtained in Example 12 and 1.5 molar equivalents of boron tribromide (BBr3) were used. Then the resulting product was separated by preparative TLC to give 28 mg of the title compound in a yield of 60%.
Workup
- customThen the resulting product was separated by preparative TLC
Sources & evidence
- ORD record