Ethanol → Ethyl 2-thiazoleacrylate
Reaction equation
[S:1]1[CH:5]=[CH:4][N:3]=[C:2]1[CH:6]=[CH:7][C:8]([OH:10])=[O:9].S(=O)(=O)(O)O.[CH2:16](O)[CH3:17]>>[S:1]1[CH:5]=[CH:4][N:3]=[C:2]1[CH:6]=[CH:7][C:8]([O:10][CH2:16][CH3:17])=[O:9]Participants
4
Procedure
A solution of 2-thiazoleacrylic acid (26.76 g) and concentrated sulphuric acid (10 ml) in ethanol (150 ml) was refluxed for 18 hours. The solution was partially evaporated and dissolved in water. This solution was extracted with ether and the etheral extracts were evaporated to give ethyl 2-thiazoleacrylate.
Workup
- customThe solution was partially evaporated
- dissolutiondissolved in water
- extractionThis solution was extracted with ether
- customthe etheral extracts were evaporated
Sources & evidence
- ORD record
- ord-701e40adb0124f1f984272a6cd748fbc
- Source dataset
- uspto-grants-1979_05
- Patent number
- US04154834
Reaction notes
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