Sodium Hydroxide → 4-(Pyridin-4-yl)-1,3-thiazole-2-carboxylic acid
Reaction equation
[N:1]1[CH:6]=[CH:5][C:4]([C:7]2[N:8]=[C:9]([C:12]([O:14]CC)=[O:13])[S:10][CH:11]=2)=[CH:3][CH:2]=1.[OH-].[Na+]>C(O)C>[N:1]1[CH:6]=[CH:5][C:4]([C:7]2[N:8]=[C:9]([C:12]([OH:14])=[O:13])[S:10][CH:11]=2)=[CH:3][CH:2]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
To the obtained ethyl 4-(4-pyridyl)-2-thiazolecarboxylate (1.5 g) in ethanol (10 ml) solution was added 1 N sodium hydroxide solution (10 ml), and the solution was stirred at room temperature for 2 hours. The reaction solution was concentrated and the residue was dissolved in water, to which was added 1 N hydrochloric acid (10 ml). The precipitate was filtered, washed with water and dried to give the title compound (1.105 g).
Workup
- concentrationThe reaction solution was concentrated
- dissolutionthe residue was dissolved in water, to which
- additionwas added 1 N hydrochloric acid (10 ml)
- filtrationThe precipitate was filtered
- washwashed with water
- customdried
Sources & evidence
- ORD record
- ord-1c1939191b4a42e48702b0cb43e124b6
- Source dataset
- uspto-grants-2002_03
- Patent number
- US06359134B1
Reaction notes
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