Sodium Hydroxide → 4-(2-Methoxyphenyl)-3-methylbenzoic acid
Reaction equation
[OH-].[Na+].[CH3:3][O:4][C:5]1[CH:10]=[CH:9][CH:8]=[CH:7][C:6]=1[C:11]1[CH:16]=[CH:15][C:14]([C:17]([O:19]C)=[O:18])=[CH:13][C:12]=1[CH3:21]>CCO>[CH3:3][O:4][C:5]1[CH:10]=[CH:9][CH:8]=[CH:7][C:6]=1[C:11]1[CH:16]=[CH:15][C:14]([C:17]([OH:19])=[O:18])=[CH:13][C:12]=1[CH3:21]Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 60 °C
Procedure
Sodium hydroxide (5M; 4.7 mL; 23.4 mmol; 3 eq.) was added to a solution of methyl 2′-methoxy-2-methylbiphenyl-4-carboxylate (2 g; 7.8 mmol; 1 eq.) in EtOH (60 mL) and the reaction mixture was stirred at 60° C. for one hour then concentrated in vacuo. The residue was taken up in water (400 mL) and washed with ethyl acetate (2×200 mL) then acidified to pH 2 with conc. HCl. The solution was concentrated to ca. 80 mL, the precipitate filtered off and dried to afford the title compound as a brown solid.