4-Fluoro-2-nitrophenol → 2-Amino-4-fluorophenol

HRID 337329Notes

Reaction equation

HRID 337329 reaction equation
[F:1][C:2]1[CH:7]=[CH:6][C:5]([OH:8])=[C:4]([N+:9]([O-])=O)[CH:3]=1>C(O)C.[Pd]>[NH2:9][C:4]1[CH:3]=[C:2]([F:1])[CH:7]=[CH:6][C:5]=1[OH:8]

Participants

4

Reactant 1

HCID 1362364-Fluoro-2-nitrophenol

Product 1

HCID 27359172-Amino-4-fluorophenolYield 86.9%

Reagents, catalysts & solvents 2

HCID 23938PalladiumCatalystHCID 702EthanolSolvent

Procedure

300 mg of 4-fluoro-2-nitrophenol was dissolved in 3 ml of ethanol, and 120 mg of 10% palladium/carbon was added and stirred under hydrogen atmosphere at room temperature for 1 hour. After the insoluble matter was filtered off, the filtrate was distilled off under reduced pressure to yield 211 mg of the title compound.

Workup

  1. filtrationAfter the insoluble matter was filtered off
  2. distillationthe filtrate was distilled off under reduced pressure

Sources & evidence

ORD record
ord-3bdbe08535b049f4b504bdb13705ee74
Source dataset
uspto-grants-2014_11
Patent number
US08889727B2

Reaction notes

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