Sodium Hydroxide → Diazene, (nitrophenyl)phenyl-, (E)-

HRID 441511

Reaction equation

[OH-].[Na+].O[C:4]1[C:9](C(CC)(C)C)=[CH:8][C:7](C(CC)(C)C)=[CH:6][C:5]=1[N:20]=[N:21][C:22]1[CH:27]=[CH:26][CH:25]=[CH:24][C:23]=1[N+:28]([O-:30])=[O:29]>>[N+:28]([C:23]1[CH:24]=[CH:25][CH:26]=[CH:27][C:22]=1[N:21]=[N:20][C:5]1[CH:4]=[CH:9][CH:8]=[CH:7][CH:6]=1)([O-:30])=[O:29]

Participants

Reactant 2

HCID 14798Sodium Hydroxide

HCID 1041112-Nitro-2'-hydroxy-3',5'-bis(tert-amyl)azobenzene

Product 1

HCID 142206Diazene, (nitrophenyl)phenyl-, (E)-

Procedure

The same procedure as described in Example 1 was carried out except that the 27.4 grams of 50% sodium hydroxide was used with 155 grams of 2'-hydroxy-3',5'-di-tert-amyl-2-nitroazobenzene to give a ratio of moles of alkali to moles of o-nitroazobenzene intermediate of 0.848/1 compared to the ratio of 0.42/1 employed in Example 1.

Sources & evidence

ORD record: ord-2d3d8654b82045978a53888e521b7675
Source dataset: uspto-grants-1977_08
DOI: 10.6084/m9.figshare.5104873.v1
Patent number: US04041044

Linked notes

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