Formaldehyde → Sodium Hydroxide

HRID 486179

Reaction equation

HRID 486179 reaction equation
[C:1]1([OH:7])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.C=O.B([O-])=[O:11].[Na+:13]>>[OH-:7].[Na+:13].[OH-:11].[Na+:13].[C:1]1([OH:7])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1

Participants

5

Reactant 3

HCID 712Formaldehyde3×HCID 996Phenol2×HCID 145326Sodium metaborate

Product 2

HCID 14798Sodium HydroxideYield 50%HCID 19597145NaOH phenol

Procedure

A reactor equipped as in Examples A and B was charged with phenol and formaldehyde in a formaldehyde to phenol molar ratio (F/P) of about 1.5:1. The formaldehyde was charged as a 50% aqueous solution. About 3% by weight based on the total charge of sodium metaborate was added and sufficient 50% aqueous sodium hydroxide to give a mole ratio (NaOH/phenol) of about 0.054:1. The mixture was heated to about 65° C. and held until the free formaldehyde fell to less than about 1.75%. The mixture was cooled to about 55° C. and distilled under vacuum to a non-volatile solids content of about 65%.

Workup

  1. customA reactor equipped as in Examples A and B
  2. additionwas added

Sources & evidence

ORD record
ord-e12fc928095344ec8ff5b476c3af94ff
Source dataset
uspto-grants-1994_03
Patent number
US05290843

Linked notes

Loading…