Sodium Iodide → Dimethyl 3-(3-bromo-5-thienylmethoxy)phthalate

Participants

Reaction Steps

In a manner similar to that of Example 9(i), by reaction of 20 g (103 mmol) of (3-bromo-5-thienyl)methanol with 21.6 mL (155 mmol) of triethylamine and 8.8 mL (114 mmol) of methanesulphonyl chloride, followed by 500 mg (3.5 mmol) of sodium iodide, 14.3 g (103 mmol) of potassium carbonate and 21.7 g (103 mmol) of dimethyl 4-hydroxyphthalate, the desired product is obtained in the form of orange-coloured crystals (m.p.=65° C.; m=27 g; Y=74%).

Provenance & Evidence