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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 5295Generated: October 26, 2026

4-Methoxy-1-naphthol → 4,4'-Dimethoxy[2,2'-binaphthalene]-1,1'-diol

https://huagongshe.com/reaction/5295

Reaction equation

Participants

RoleNameHCIDCharge
Reactant4-Methoxy-1-naphtholHCID 66542—
Reactant1(2H)-Naphthalenone, 4-methoxy-2-(4-methoxy-1-oxo-2(1H)-naphthalenylidene)-HCID 5378814—
CatalystSilver(II) oxideHCID 92152—
SolventChloroformHCID 6212—
Product4,4'-Dimethoxy[2,2'-binaphthalene]-1,1'-diolHCID 13284299—

Reaction Steps

Under an atmosphere of nitrogen, a mixture of 5.0 g of 4-methoxy-1-naphthol and 50 mL chloroform was mechanically stirred with 10.0 g silver oxide until the conversion to Russig's Blue was complete. The unreacted silver oxide was filtered and washed with chloroform. The filtrate and chloroform washings were combined and stirred with 4.9 g of 4-methoxy-1-naphthol until the solution turned gray. The solution was then concentrated to 50 mL and the resulting precipitate was filtered, washed with chloroform and dried to yield 3.18 g of 1,1'-dimethoxy-3,3'-binaphthyl-4,4'-diol as a light gray solid. The structure was confirmed by NMR.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS05244771
Source datasetuspto-grants-1993_09
ORD IDord-c2d3f9dc48864913be85c1333e2753ce
Source noteuspto-grants-1993_09