4'-Methoxyacetophenone → 2-Amino-4-(4-methoxyphenyl)thiazole

HRID 644493

Reaction equation

[CH3:1][O:2][C:3]1[CH:8]=[CH:7][C:6]([C:9](=O)[CH3:10])=[CH:5][CH:4]=1.[NH2:12][C:13]([NH2:15])=[S:14]>>[NH2:15][C:13]1[S:14][CH:10]=[C:9]([C:6]2[CH:7]=[CH:8][C:3]([O:2][CH3:1])=[CH:4][CH:5]=2)[N:12]=1

Participants

Reactant 2

HCID 74764'-Methoxyacetophenone

HCID 2723790Thiourea

Product 1

HCID 1596442-Amino-4-(4-methoxyphenyl)thiazoleYield 85.2%

Procedure

Using 4′-methoxyacetophenone and thiourea as the raw materials, the same operation as the Example 395(1) gave the title compound.

Sources & evidence

ORD record: ord-165c080030b04fa9a6f1a3ddfe14a777
Source dataset: uspto-grants-2010_04
DOI: 10.6084/m9.figshare.5104873.v1
Patent number: US07700655B2

Linked notes

Loading…