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Water → 3-Methoxy-4-{4-[4-(trifluoromethyl)phenoxy]phenoxy}pent-2-en-1-ol

HRID 647384
Notes
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Reaction equation

HRID 647384 reaction equation
[H-].[H-].[H-].[H-].[Li+].[Al+3].[F:7][C:8]([F:35])([F:34])[C:9]1[CH:33]=[CH:32][C:12]([O:13][C:14]2[CH:31]=[CH:30][C:17]([O:18][CH:19]([CH3:29])[C:20]([O:27][CH3:28])=[CH:21][C:22](OCC)=[O:23])=[CH:16][CH:15]=2)=[CH:11][CH:10]=1.[H-].O>CCOCC>[F:7][C:8]([F:34])([F:35])[C:9]1[CH:10]=[CH:11][C:12]([O:13][C:14]2[CH:31]=[CH:30][C:17]([O:18][CH:19]([CH3:29])[C:20]([O:27][CH3:28])=[CH:21][CH2:22][OH:23])=[CH:16][CH:15]=2)=[CH:32][CH:33]=1
ParticipantsProcedureWorkupSources & evidenceReaction notes

Participants

6

Reactant 4

HCID 962WaterHCID 166653HydrideHCID 21226445Aluminium lithium hydrideHCID 53713180HCID 53713180, compound

Product 1

HCID 537578573-Methoxy-4-{4-[4-(trifluoromethyl)phenoxy]phenoxy}pent-2-en-1-ol

Reagents, catalysts & solvents 1

HCID 3283
Diethyl Ether
Solvent
3×

Procedure

To a slurry of LiAlH4 (400 mg) in anhydrous ether (20 ml) is added dropwise at 0°, a solution of ethyl 4-[4-(4-trifluoromethylphenoxy)phenoxy]-3-methoxy-2-pentenoate (1.2 g) in ether (10 ml). After addition is complete, the reaction mixture is stirred for about 10 minutes. Excess hydride is decomposed with wet ether and water. After filtration, the filtrate is concentrated to give the alcohol, 4-[4-(4-trifluoromethylphenoxy) phenoxy]-3-methoxy-2-penten-1-ol.

Workup

  1. additionAfter addition
  2. filtrationAfter filtration
  3. concentrationthe filtrate is concentrated

Sources & evidence

ORD record
ord-be93f812b9224915a22b7be7dacda2ea
Source dataset
uspto-grants-1983_10
DOI
10.6084/m9.figshare.5104873.v1
Patent number
US04408076

Reaction notes

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On this pageParticipantsProcedureWorkupSources & evidenceReaction notes