Sodium Hydroxide → 5-Bromo-2-methoxy-4-methylbenzoic acid
Reaction equation
[Br:1][C:2]1[C:3]([CH3:14])=[CH:4][C:5]([O:12][CH3:13])=[C:6]([CH:11]=1)[C:7]([O:9]C)=[O:8].[OH-].[Na+]>CCO.O>[Br:1][C:2]1[C:3]([CH3:14])=[CH:4][C:5]([O:12][CH3:13])=[C:6]([CH:11]=1)[C:7]([OH:9])=[O:8]Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
Methyl 5-bromo-2-methoxy-4-methylbenzoate (11.64 g, 0.045 mol) was dissolved in a mixture of EtOH:H2O (1:1 ratio, 150 mL), NaOH (5.8 g, 0.145 mol) was added and reaction mixture was refluxed for 30 min. The EtOH solvent was removed from the mixture by distillation which leads to precipitation of the desired product as its sodium salt. The residue was diluted with H2O (75 mL) and the pH was adjusted to ˜2 with concentrated HCl. The precipitate was collected by filtration, washed with H2O (3×50 mL) and air dried to give pure 5-bromo-2-methoxy-4-methylbenzoic acid 12a (9 g, 82% yield) as a beige solid.