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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 7482Generated: October 24, 2026

Hydrochloric Acid → 4-Chloro-6-methoxy-7-(3-morpholinopropoxy)cinnoline

https://huagongshe.com/en/reaction/7482

Reaction equation

Participants

RoleNameHCIDCharge
ReactantHydrochloric AcidHCID 313—
ReactantPotassium IodideHCID 4875—
ReactantPotassium CarbonateHCID 11430—
Reactant4-(3-Chloropropyl)morpholineHCID 95834—
Reactant4-Chloro-7-hydroxy-6-methoxycinnolineHCID 135752523—
SolventIsopropanolHCID 3776—
SolventDimethylformamideHCID 6228—
SolventMethanol--water (1/1)HCID 22242641—
Product4-Chloro-6-methoxy-7-(3-morpholinopropoxy)cinnolineHCID 21991059—

Reaction Conditions

Temperature80 °C

Reaction Steps

The starting material 4-chloro-6-methoxy-7-(3-morpholinopropoxy)cinnoline hydrochloride was obtained by adding 1-chloro-3-morpholinopropane (190 mg, 0.95 mmol), (prepared as described in U.S. Pat. No. 4,004,007), to a suspension of 4-chloro-7-hydroxy-6-methoxycinnoline (0.2 g, 0.95 mmol), (prepared as described for the starting material in Example 10), in DMF (5 ml) containing potassium carbonate (327 mg, 2.3 mmol) and potassium iodide (15 mg, 0.095 mmol). After heating at 80° C. for 2 hours, potassium carbonate (65 mg, 0.47 mmol) and more 1-chloro-3-morpholinopropane (95 mg, 0.47 mmol) were added. After stirring for 4 hours at 80° C. the reaction mixture was cooled and 7M hydrogen chloride in isopropanol (407 μl) was added. The solution was poured onto a Diaion (trade mark of Mitsubishi) HP20SS column, using water/methanol (100/0 to 0/100 as a gradient) to give 4-chloro-6-methoxy-7-(3-morpholinopropoxy)cinnoline as an hydrochloride salt (175 mg, 44%).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07087602B2
Source datasetuspto-grants-2006_08
ORD IDord-245f2870f5024f29a93ebbc4e31b8a82
Source noteuspto-grants-2006_08