Acetic Acid → 4-Amino-3-fluoro-5-methoxybenzoic acid
Reaction equation
[F:1][C:2]1[CH:3]=[C:4]([CH:8]=[C:9]([O:14][CH3:15])[C:10]=1[N+:11]([O-])=O)[C:5]([OH:7])=[O:6].CC(O)=O.[H][H]>CO>[NH2:11][C:10]1[C:9]([O:14][CH3:15])=[CH:8][C:4]([C:5]([OH:7])=[O:6])=[CH:3][C:2]=1[F:1]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
A solution of 3-fluoro-5-methoxy-4-nitrobenzoic acid (obtained above), HOAc (5 mL) and MeOH (5 mL) was hydrogenated using a hydrogen balloon overnight. The solution was then filtered through celite and concentrated to a red solid (590 mg, 66%). [M+H] calc'd for C8H8FNO3, 186. found 186.
Workup
- filtrationThe solution was then filtered through celite
- concentrationconcentrated to a red solid (590 mg, 66%)
Sources & evidence
- ORD record
- ord-0f237409cde246e38304014868474e8b
- Source dataset
- uspto-grants-2011_09
- Patent number
- US08026234B2
Reaction notes
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