Nitric Acid → Silver laurate

Reaction equation

[C:1]([OH:14])(=[O:13])[CH2:2][CH2:3][CH2:4][CH2:5][CH2:6][CH2:7][CH2:8][CH2:9][CH2:10][CH2:11][CH3:12].[N+]([O-])(O)=O.[N+]([O-])([O-])=O.[Ag+:23]>C(OCCCC)(=O)C>[C:1]([O-:14])(=[O:13])[CH2:2][CH2:3][CH2:4][CH2:5][CH2:6][CH2:7][CH2:8][CH2:9][CH2:10][CH2:11][CH3:12].[Ag+:23]

Participants

Procedure

A solution of 11g of lauric acid in 100ml of butyl acetate was maintained at 10° C, and with stirring with a stirrer 100ml of a dilute aqueous solution of nitric acid (having a pH of 2.0 at 25° C) was mixed with the above solution. With continued stirring, 50ml of an aqueous solution (cooled to 0° C) of a silver nitrate.ammonium complex salt containing 8.5g of silver nitrate was added over the course of 1 minute to allow the lauric acid to react with the silver ion. Silver laurate crystals were obtained in the form of spindles each of which measured about 1 micron along its long side and about 0.05 micron along its short side. The silver salt obtained was washed with water, and then with methanol, and 3.0g of polyvinyl butyral and 20ml of isopropyl alcohol, both based on 2.7g of the silver laurate, were added. The mixture was processed in a ball mill to form a polymer dispersion of the silver salt.