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Diethyl Ether → HCID 67204228、化合物

HRID 1036812
ノート
印刷プレビュー

反応式

HRID 1036812 の反応式
[CH2:1]([O:8][C:9]1[CH:14]=[CH:13][C:12]([CH2:15][CH2:16]O)=[CH:11][C:10]=1[F:18])[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1.C(Br)(Br)(Br)[Br:20].C1C=CC(P(C2C=CC=CC=2)C2C=CC=CC=2)=CC=1.CCOCC>C(Cl)Cl>[CH2:1]([O:8][C:9]1[CH:14]=[CH:13][C:12]([CH2:15][CH2:16][Br:20])=[CH:11][C:10]=1[F:18])[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1
参加物実験手順後処理出典と根拠反応ノート

参加物

6

反応物 4

HCID 3283Diethyl EtherHCID 11205Carbon tetrabromideHCID 11776TriphenylphosphineHCID 672034892-(4-(Benzyloxy)-3-fluorophenyl)ethanol

生成物 1

HCID 67204228HCID 67204228、化合物収率 93.5%

試薬・触媒・溶媒 1

HCID 6344Dichloromethane溶媒

実験手順

To a solution of 2-(4-benzyloxy-3-fluoro-phenyl)-ethanol (1.0 g, 4.0 mmol) and CBr4 (1.5 g, 4.5 mmol) in CH2Cl2 (10 mL), was PPh3 (1.2 g, 4.5 mmol) added portionwise at 0° C. The reaction mixture stirred for 2 hours at the same temperature. The reaction was concentrated under vacuum and the residue was stirred in ether (10 mmol). The solid, mainly triphenylphosphine oxide, was filtrated off and the filtrate was concentrated under vacuum. The residue was purified over SiO2 to afford the desired compound (1.15 g, 93.5%) as a white crystal. 1H NMR (400 MHz, DMSO-d6) δ 7.36-7.49 (m, 5H), 7.17-7.23 (m, 2H), 7.03-7.05 (m, 1H), 5.18 (s, 2H), 3.72 (t, 2H), 3.08 (t, 2H). LCMS 273.4 [MH+].

後処理

  1. additionadded portionwise at 0° C
  2. concentrationThe reaction was concentrated under vacuum
  3. filtrationThe solid, mainly triphenylphosphine oxide, was filtrated off
  4. concentrationthe filtrate was concentrated under vacuum
  5. customThe residue was purified over SiO2

出典と根拠

ORDレコード
ord-69fcf040dd564316b098d2f5e8cf1134
出典データセット
uspto-grants-2013_10
DOI
10.6084/m9.figshare.5104873.v1
特許番号
US08546429B2

反応ノート

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