戻る
化工社化工社 化学情報印刷レポート · 研究参考用
HRID 11014作成日:2026年10月25日

Triethylamine → 4-Amino-9-methoxypyrrolo[3,4-c]carbazole-1,3(2H,6H)-dione

https://huagongshe.com/reaction/11014

反応式

関与物質

役割名称HCID仕込み量
反応物TriethylamineHCID 8471—
反応物P,P-Diphenylphosphinic azideHCID 199401—
反応物9-Methoxy-1,3-dioxo-1,2,3,6-tetrahydropyrrolo[3,4-c]carbazole-4-carboxylic acidHCID 11843005—
溶媒tert-ButanolHCID 6386—
溶媒Trifluoroacetic acid methylene chlorideHCID 21863450—
生成物4-Amino-9-methoxypyrrolo[3,4-c]carbazole-1,3(2H,6H)-dioneHCID 1184300693.4%

反応手順

Diphenylphosphoryl azide (1.81 mL, 8.38 mmol) was added to a mixture of the 9-methoxy-1,3-dioxo-1,2,3,6-tetrahydropyrrolo[3,4-c]carbazole-4-carboxylic acid (2.55 g, 8.22 mmol), prepared as in example 4, and Et3N (1.17 mL, 8.38 mmol) in anhydrous t-butanol (300 mL) and the mixture was refluxed under an atmosphere of nitrogen for 16 h. The solution was concentrated in vacuo and the residue partitioned between EtOAc and saturated aqueous NaHCO3. Insoluble material was removed by filtration of the two layers through Celite, washing through with more EtOAc. The organic phase was dried, the drying agent was removed and the solution was concentrated to dryness and gave a yellow solid. This material was dissolved in CH2Cl2/trifluoroacetic acid (1:1) (200 mL) and the solution was held at room temperature for 1 h. After concentration in vacuo the residue was partitioned between EtOAc and saturated aqueous NaHCO3 solution. The EtOAc solution was dried, the drying agent was removed and the solution was concentrated to dryness to give an orange solid which was adsorbed onto silica and chromatographed. Elution with ethyl acetate/petroleum ether (1:1) followed by ethyl acetate and then methanol/ethyl acetate (1:9) gave 4-amino-9-methoxypyrrolo[3,4-c]carbazole-1,3(2H,6H)-dione (6) as an orange powder (2.16 g, 93%), mp 342–345° C. 1H NMR δ [(CD3)2SO] 11.18 (s, 1H), 10.78 (br s, 1H), 8.18 (d, J=2.5 Hz, 1H), 7.29 (d, J=8.7 Hz, 1H), 7.01 (dd, J=8.7, 2.5 Hz, 1H), 6.83 (s, 1H), 6.28 (br s, 2H), 3.82 (s, 3H). Found: C, 63.05; H, 3.99; N, 14.05. C15H11N3O3, 1/2H2O requires C, 63.04; H, 4.06; N, 14.7.

情報源と証拠

DOI10.6084/m9.figshare.5104873.v1
特許番号US07094798B1
出典データセットuspto-grants-2006_08
ORD IDord-a73b7af270cf42e6b11cc84eb5367f8f
出典メモuspto-grants-2006_08