[CH2:1](OC1C(F)=CC(Br)=C2C=1C=CN2C)[C:2]1C=CC=C[CH:3]=1.[Br:21][C:22]1[CH:23]=[C:24]2[O:34][CH2:33][CH2:32][O:31][C:25]2=[C:26]2[C:30]=1[NH:29][CH:28]=[CH:27]2>>[Br:21][C:22]1[CH:23]=[C:24]2[O:34][CH2:33][CH2:32][O:31][C:25]2=[C:26]2[C:30]=1[N:29]([CH2:1][CH2:2][CH3:3])[CH:28]=[CH:27]2Following the procedure (step 2, scheme 33) used to prepare compound 33-3, compound 40-2 gave compound 40-3 in 90% yield as a yellow solid. LCMS: calc 295.0 found 296.0 [MH]+.
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